javascript 一問

不愛回家 2020-3-30 18:14:47 初學
唔識個loop 應該點寫
有冇高人指點一下

:^(

好呀好呀好呀好呀 2020-3-30 18:19:23 forloop // do sth on x
{
　forloop // do sth on y
　{
　　forloop // do sth on z
　　{

　　}
　}
}

好呀好呀好呀好呀 2020-3-30 18:20:24

forloop // do sth on x
{
forloop // do sth on y
{
forloop // do sth on z
{
　if (x - 2y + 3z == 0)
then print result
}
}
}

迷迷糊糊 2020-3-30 18:23:35 for (let x = 1; x <= 5; x++)
for (let y = 6; y <= 10; y++)
for (let z = 3; z <= 7; z++)

不愛回家 2020-3-30 18:36:52 我仲差啲咩真係唔係好識啲詳細既code...

:^(

大盲西 2020-3-30 18:40:53 js 有if then 架咩

:^(

不愛回家 2020-3-30 18:45:27 我唔識

:^(

今晚要交

利蹦辣 2020-3-30 18:51:03 重新學過啦咁你

:^(

google下for loop點用

大盲西 2020-3-30 18:53:49 都唔止係for loop 問題

:^(

滿街腳步突然靜了 2020-3-30 18:57:29 中學功課黎？

Servlet 2020-3-30 19:30:35 啱啱寫完，但唔想害左你。其實樓上已經俾左一半答案。下一半係呢度
講明先，其實我唔識javascript.

if ( (x-(2*y)+(3*z)) == 0){
console.log("x = " + x + ", y = " + y + ", z =" + z);
}
for loop syntax, https://www.w3schools.com/js/js_loop_for.asp

你可以用以下呢個寫。
https://codepen.io/pen/

手一黏便緊(UTC+9 2020-3-30 19:33:13 你已經害左佢

Servlet 2020-3-30 19:36:20

:^(

你啱。

何君妖 2020-3-30 22:10:45 [1, 2, 3, 4, 5].forEach(x => {
[6, 7, 8, 9, 10].forEach(y => {
[3, 4, 5, 6, 7].forEach(z => {
if (x - 2 * y + 3 * z == 0) {
console.log("x = " + x + ", y = " + y + ", z =" + z);
};
})
})
});

➿➿ 2020-3-31 13:14:01 重讀啦
錯撚哂

:^(

➿➿ 2020-3-31 13:32:26

 for x in range(1,6):
  for y in range(6,11):
    for z in range(3,8):
      if ( x - 2 * y + 3 * z  == 0 ):
        print("x={}, y={}, z={}".format(x,y,z))

eventually 2020-3-31 13:51:07 呢條問題可以變得好有趣，如果想optimize個time complexity嘅話

:^(

，例如呢個case係有辦法唔洗寫三個loop，因為你係搵緊一個matrix嘅null space，loop完頭兩個variable，最後嗰個variable如果係within range嘅話，佢個value必然係unique，所以唔洗loop佢

妳是我心上人 2020-3-31 20:49:02 唔好水鳩人啦
咁簡單都話有趣

eventually 2020-3-31 21:11:41 唔係呀，而家講緊O(n^3)同O(n^2)嘅分別喎

SinkingBoat 2020-3-31 21:39:55 樓主企都未企到你就教人跑

:^(

風間.徹 2020-4-1 20:49:52

var x = [1, 2, 3, 4, 5];
var y = [6, 7, 8, 9, 10];

x.forEach(xNum => {
    y.forEach(yNum => {
        result = xNum + 2 * yNum;
        remainer = (xNum + 2 * yNum) % 3;
        if (!remainer) {
            console.log("x: " + xNum + " y: " + yNum + " z: " + result / 3);
        }
    })
})