python 題目求指點
簫塞胸器中 2019-2-21 18:14:14
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自己個code
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我嘗試去run 佢但係有several case 係runtime error 而我又睇唔到個d case 有無巴打可以指點下我話比我聽個code ge盲眼位係邊到 thank you
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咩嚕咩嚕咩 2019-2-21 18:15:47 手機影mon
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簫塞胸器中 2019-2-21 18:25:08
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地爆天星 2019-2-21 19:38:21 發現樓主
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https://stackoverflow.com/questions/54789625/pillar-jumpers-in-python
簫塞胸器中 2019-2-21 19:50:44 一撚定係啦 仲識上lihkg
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簫塞胸器中 2019-2-21 19:51:36 有無人幫手
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Billybug大哥 2019-2-21 19:56:04 S 係 strength
即係佢可以由i跳去i+S咁?
求銀祈 2019-2-21 19:57:14 係咪啲loop loop好撚多次呀?
簫塞胸器中 2019-2-21 20:00:33 係 我發現我漏左呢樣野 但我唔知點樣可以add 落個function
簫塞胸器中 2019-2-21 20:01:56 呢個都係其中一個原因 咁我可以點樣改善呢個問題
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Billybug大哥 2019-2-21 20:10:30 S = N-1 no matter what J is.
利伸:9up

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billyhk 2019-2-21 20:39:53 你唔講你段code 既logic 叫人點幫你呀
不可一生 2019-2-21 20:43:58 手機影
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又唔講你段code 既logic 點 run , 好難幫到你
唯有幫你google 下
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https://stackoverflow.com/questions/54789625/pillar-jumpers-in-python
billyhk 2019-2-21 20:51:50 用S 來做binary search

Start = max difference between each pillar

End= Number of pillar/J
簫塞胸器中 2019-2-21 23:20:26 但係要搵minimum strength ge 話 用binary search 唔會好唔方便咩
女既都係偷呃拐騙 2019-2-21 23:25:16 點解樓主唔用pycharm
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靚好多function好好多
項少龍 2019-2-21 23:27:10 Dynamic programming 會唔會好啲
billyhk 2019-2-21 23:35:40 唔會,binary search 每次check canJump(S) 好簡單咋喎
簫塞胸器中 2019-2-21 23:46:42 我而岩岩起步學programming 可唔可以講多d thx
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女既都係偷呃拐騙 2019-2-21 23:47:50 PyCharm係ide嚟
如果你係學生既話條license係免費
簫塞胸器中 2019-2-21 23:49:06 我試下先
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同埋想問下點樣可以將 max_jump = strength + current_position 然後用max_jump 取代function 入面個個for loop 個上限 from number_of_pillars to max_jump
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簫塞胸器中 2019-2-21 23:50:09 個陣我要install 個platform 然後個frd 叫我用spyder 唔好煩
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而家down 黎試下撚下先
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女既都係偷呃拐騙 2019-2-21 23:51:00 你個fd真係夠晒老友
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簫塞胸器中 2019-2-21 23:51:30 而家去左exchange 我都係識左佢幾日
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女既都係偷呃拐騙 2019-2-21 23:53:16 去jetbrains註冊個Student ac先
然後verify個學生email address就會有free license比你用
裝咗之後paste你d code落pycharm睇下佢會唔會出咩error msg或者suggestion